x^2-50x-625=0

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Solution for x^2-50x-625=0 equation:



x^2-50x-625=0
a = 1; b = -50; c = -625;
Δ = b2-4ac
Δ = -502-4·1·(-625)
Δ = 5000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{5000}=\sqrt{2500*2}=\sqrt{2500}*\sqrt{2}=50\sqrt{2}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-50)-50\sqrt{2}}{2*1}=\frac{50-50\sqrt{2}}{2} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-50)+50\sqrt{2}}{2*1}=\frac{50+50\sqrt{2}}{2} $

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